Velocity-displacement graph of a particle mov | vedclass

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Question

$\mathrm{V}=-\mathrm{mS}+\mathrm{V}_{0}$

$\left(\frac{d V}{d S}\right)=-m$

$a=V\left(\frac{d V}{d S}\right)=\left[-m S+V_{0}\right][-m]$

$\ma

Vedclass · Accepted Answer

acceleration versus displacement graph is straight line

Vedclass · Answer

$\mathrm{V}=-\mathrm{mS}+\mathrm{V}_{0}$

$\left(\frac{d V}{d S}\right)=-m$

$a=V\left(\frac{d V}{d S}\right)=\left[-m S+V_{0}\right][-m]$

$\mathrm{a}=\mathrm{m}^{2} \mathrm{S}-\mathrm{m} \mathrm{V}_{0}$

This is eqn. of straight line.

Velocity-displacement graph of a particle moving in a straight line is as shown in figure

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