Velocity-displacement graph of a particle moving in a straight line is as shown in figure

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2.Motion in Straight Line

easy

Velocity-displacement graph of a particle moving in a straight line is as shown in figure

A

magnitude of acceleration of particle is constant

B

magnitude of acceleration of particle is increasing

C

acceleration versus displacement graph is straight line

D

acceleration versus displacement graph is parabola

Solution

$\mathrm{V}=-\mathrm{mS}+\mathrm{V}_{0}$

$\left(\frac{d V}{d S}\right)=-m$

$a=V\left(\frac{d V}{d S}\right)=\left[-m S+V_{0}\right][-m]$

$\mathrm{a}=\mathrm{m}^{2} \mathrm{S}-\mathrm{m} \mathrm{V}_{0}$

This is eqn. of straight line.

Standard 11

Physics

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